How to find second highest salary using Ranking Function (DENSE_RANK()) in SQL?

Table Name : SalaryDetails

ID	Salary
1	1000
2	500
3	750
4	500
5	350
6	750

SELECT a.Name,a.salary
FROM  (   SELECT Name,salary,DENSE_RANK() over (ORDER BY salary desc) AS Rank FROM salaryDetails  )  as a where Rank = 2